Xml 尖括号更改为 & 和 lt 分号

Question

I have following code and my message is in xml formatted and it is huge data.我有以下代码，我的消息是 xml 格式的，它是巨大的数据。 I am not getting my message in and .我没有收到我的消息和。 Xml angle brackets are now transformed. Xml 尖括号现在已转换。 I would like to have angle brackets rather than ampersand lt semicolon.我想要尖括号而不是与号 lt 分号。

<createOrderRequestType xmlns:ns2="http://xmlns.oracle.com/communications/ordermanagement">
    <msg>&lt;head&gt;&lt;/head&gt;
&lt;/body&gt;
</msg>
</createOrderRequestType>

<msg>
<head> </head>
<body> </body>
</msg>

public CreateOrderResponseType createAncillariesBySoloOrderId(String soloOrderId) {
        String message = findOrderBySoloOrderId(soloOrderId);

        final Pattern pattern = Pattern.compile("<msg xmlns=\"\">(.+?)</msg>", Pattern.DOTALL);
        final Matcher matcher = pattern.matcher(message);
        matcher.find(); 
        String msgStr =  matcher.group(1) ;
        log.info("message = " + msgStr );
CreateOrderRequestType createOrderRequestType = new CreateOrderRequestType() ;      
        Document doc;
        try {
            doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument();
            Element msg = doc.createElement("msg");
            msg.setTextContent(msgStr);
            doc.appendChild(msg);
            createOrderRequestType.getAny().add((Element) doc.getFirstChild());

            StringWriter sw1 = new StringWriter();
            JAXB.marshal(createOrderRequestType, sw1);
            String xmlString = sw1.toString();
            log.info("xmlString = " + xmlString); 

        } catch (ParserConfigurationException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }       
 return getOSMService(osmServiceUrl).createOrder(createOrderRequestType);
}   



public class CreateOrderRequestType {

    @XmlAnyElement(lax = true)
    protected List<Object> any;

public List<Object> getAny() {
        if (any == null) {
            any = new ArrayList<Object>();
        }
        return this.any;
    }

}

Answer 1

It depends of XSD这取决于 XSD

But, i think it will be:但是，我认为它将是：

...
@XmlRootElement(name = "CreateOrderRequestType") // or probably (name = "CreateOrderRequest")
public class CreateOrderRequestType {
...

and for response too也为了回应

...
@XmlRootElement(name = "CreateOrderResponseType") // or probably (name = "CreateOrderResponse")
public class CreateOrderResponseType{
...

Xml 尖括号更改为 & 和 lt 分号

问题描述

1 个解决方案

解决方案1
0 2020-02-19 19:03:06

Xml 尖括号更改为 &amp; 和 lt 分号

问题描述

1 个解决方案

解决方案1 0 2020-02-19 19:03:06

Xml 尖括号更改为 & 和 lt 分号

解决方案1
0 2020-02-19 19:03:06