如何将值传递给作为 Python 中列表项的函数

Question

I want to pass a value as argument in a function which is a list item.

For example:

def foo(arg1, arg2):
    print(“Something is happening here”, arg1, arg2 )


l = [1,2,3, foo('want values here as arguments')] 

def foo_bar():
    x = 0, y = 1
    print(“want to pass x and y inside: “ , l[3])

Thanks ahead.

Answer 1

 def foo(arg1, arg2):
    print("Something is happening here", arg1, arg2 )


l = [1,2,3, foo] 

def foo_bar():
    x = 0
    y = 1
    print("want to pass x and y inside: " , l[3](x,y))

Answer 2

You write

l = [1,2,3,foo]

and later

print l[3](x,y)

Answer 3

In order to store the result from foo() in your list, you need to reorder the steps in your code. I recommend storing the return result from foo() as a variable:

def foo(arg1, arg2):
    print(“Something is happening here”, arg1, arg2 )



def foo_bar():
    x = 0
    y = 1
    z = foo(x, y)
    l = [1,2,3, z] 
    print(l)

Alternatively, you can create the list and then append values to it:

def foo(arg1, arg2):
    print(“Something is happening here”, arg1, arg2 )


l = [1,2,3] 


def foo_bar():
    x = 0
    y = 1
    z = foo(x, y)
    l.append(z)
    print(l)