正则表达式记事本++

Question

When using character delimited text, what code allows me to pull out specific segments within a given row? Out of a given set of data (focusing on bold):

1194459945, 11/07/2007 18:25:45,2,vnta,287.78,2, 7.783 ,2,34.111,2,1.3,2, 89.54 ,2,1485.31,26.612

Trying to get it like:

11/07/2007 7.783 89.54

Currently, the progress I've made has been: (\\w+,)(.+) ( which has given me the first two columns, but I'm stuck as to how to reach 7.783 and segment that out. Without including the entire row. I cannot put \\, because that doesn't help.

Answer 1

Something like this might work.. ^.*?,([^ ,]+)(?:.*?,){5}([^ ,]+)(?:.*?,){6}([^ ,]+).*$

Explanation:

• ^ - Start of the string / line
• .*?, - matches anything up until the first comma
• ([^ ,]+) - matches anything not a space or comma and stores it in capture group 1 (your date)
• (?:.*?,){5} - non capture group to match the fields and commas for the next 5 fields
• ([^ ,]+) - matches anything not a space or comma and stores it in capture group 2 (your 7.783)
• (?:.*?,){6} - another non capture group to match the fields and commas for the next 6 fields
• ([^ ,]+) - matches anything not a space or comma and stores it in capture group 3 (your 89.54)
• .*$ - matches anything trailing after this match to the end of string / line

Notepad++:

You can use the find and replace tool in Notepad++ to replace the strings with only the capture groups which can be accessed by using a dollar sign followed by the capture group number like so:

Find: ^.*?,([^ ,]+)(?:.*?,){5}([^ ,]+)(?:.*?,){6}([^ ,]+).*$
Replace: $1 $2 $3

Test:

Before:

1194459945,11/07/2007 18:25:45,2,vnta,287.78,2,7.783,2,34.111,2,1.3,2,89.54,2,1485.31,26.612

After:

11/07/2007 7.783 89.54