[英]Pandas changes datetime when setting value to dataframe
When I use iloc to set a datetime value to a dataframe cell, the value is changed当我使用 iloc 将日期时间值设置为数据帧单元格时,该值已更改
import datetime as dt
import pandas as pd
t = '2019-12-29 13:17:34.678000'
t = dt.datetime.fromisoformat(t)
print(t)
# 2019-12-29 13:17:34.678000
df = pd.DataFrame({'t': [t]})
print(df)
# t
# 0 2019-12-29 13:17:34.678
df.iloc[0, df.columns.get_loc('t')] = t
print(df)
# t
# 0 2019-12-29 13:17:34.678000128
Why is this happening and how can I prevent it?为什么会发生这种情况,我该如何预防?
You can apply function isoformat
that will trunc time to milliseconds removing microsecond precision:您可以应用函数
isoformat
将时间缩短到毫秒,从而消除微秒精度:
t = dt.datetime.fromisoformat(t).isoformat(timespec='milliseconds')
For details regarding isoformat, please follow: https://docs.python.org/3/library/datetime.html#datetime.time.microsecond有关 isoformat 的详细信息,请关注: https : //docs.python.org/3/library/datetime.html#datetime.time.microsecond
Please note that as documentation says, excluded time components are truncated, not rounded.请注意,正如文档所说,排除的时间分量被截断,而不是四舍五入。
This seems to be a bug in pandas 0.25.2
.这似乎是 pandas
0.25.2
一个错误。 It doesn't happen in the latest version, 1.0.1
.它不会发生在最新版本
1.0.1
。
In 0.25.2
it can be worked around by using .at
instead of .iloc
在
0.25.2
可以通过使用工作围绕.at
代替.iloc
t = '2019-12-29 13:17:34.678000'
t = dt.datetime.fromisoformat(t)
print(t)
# 2019-12-29 13:17:34.678000
df = pd.DataFrame({'t': [t]})
print(df)
# t
# 0 2019-12-29 13:17:34.678
df.at[0, 't'] = t
print(df)
# t
# 0 2019-12-29 13:17:34.678
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