SQL-DATEDIFF计算天数
[英]SQL - DATEDIFF to calculate days
问题描述
Need some help here.
在这里需要一些帮助。 I have this syntax which I think is wrong - needs a minor fix我有这样的语法，我认为这是错误的-需要小幅修复
DATEDIFF(DAY, GETDATE(), DATEADD(DAY, 3, ESI.EventStatusDate)) AS BackloggedDays
What I'm actually trying to say is whatever the event status date is (add 3 days, as a grace period) compare that to the current date (get date) and tell me how days its behind (backlogged).我实际上要说的是事件状态日期是什么（作为宽限期增加3天），将其与当前日期（获取日期）进行比较，并告诉我它的滞后天数（积压）。 If there is no back log set it at 0 days如果没有后备日志，则将其设置为0天
1 个解决方案
解决方案1
0 已采纳 2020-02-21 22:53:21
Need some help here.在这里需要一些帮助。 I have this syntax which I think is wrong - needs a minor fix我有这样的语法，我认为这是错误的-需要小幅修复
DATEDIFF(DAY, GETDATE(), DATEADD(DAY, 3, ESI.EventStatusDate)) AS BackloggedDays
What I'm actually trying to say is whatever the event status date is (add 3 days, as a grace period) compare that to the current date (get date) and tell me how days its behind (backlogged).我实际上要说的是事件状态日期是什么（作为宽限期增加3天），将其与当前日期（获取日期）进行比较，并告诉我它的滞后天数（积压）。 If there is no back log set it at 0 days如果没有后备日志，则将其设置为0天
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.