将 [("['str']", int), ("['str']", int)] 类型的列表转换为 [('str', int), ('str', int)]

Question

i have a list of type

[("['106.52.116.101']", 1), ("['45.136.108.85']", 1)]

and want to convert it to

[('106.52.116.101', 1), ('45.136.108.85', 1)]

Answer 1

There is more than one way to solve this, you can do this for example:

lst = [("['106.52.116.101']", 1), ("['45.136.108.85']", 1)]
new = [(l[0][2:-2], l[1]) for l in lst]
print(new)

Output:

[('106.52.116.101', 1), ('45.136.108.85', 1)]

Answer 2

You can use split() of string as below:

lst = [("['106.52.116.101']", 1), ("['45.136.108.85']", 1)]
print(lst)
new_lst = [(first.split('\'')[1], sec)for first, sec in lst]
print(new_lst)

output

[("['106.52.116.101']", 1), ("['45.136.108.85']", 1)]                                                                   
[('106.52.116.101', 1), ('45.136.108.85', 1)] 

Answer 3

you can use ast.literal_eval :

from ast import literal_eval

l = [("['106.52.116.101']", 1), ("['45.136.108.85']", 1)]
l = [(literal_eval(f)[0], s) for f, s in l]
l

output:

[('106.52.116.101', 1), ('45.136.108.85', 1)]

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Answer 4

Mateen Ulhaq already presented a very short and good solution.

But if the array does not always have one item in it you can use this:

[(eval(s)[0], n) for s, n in list]

As eval() interpretes python code the strings have to be syntactically correct. Also pay attention if these strings come from a user in terms of security.