python：在while循环期间在数组中查找跳过的值

Question

I have a while loop that runs through a fixed step and constantly checks if a value in an array is not equal to the while loop counter, and prints that number:

import numpy as np

values = [60.0, 75.8, 85.0, 90.0]
values = np.asarray(values)
counter = 50
while counter <= 100:
    closest = (np.abs(values - counter)).argmin()
    if (values[closest] > (counter - 1) and values[closest] <counter):
        print("we skipped a value " + str(values[closest]))
    counter = counter + 1

I wrote this code which has the mentioned functionality but it doesn't seem very elegant or efficient. Is there a quicker way to find these skipped values in Python?

Answer 1

It's hard to tell from the question exactly what you need, but this produces the same output:

for v in sorted(set(values).difference(range(50, 101))):
    print("we skipped a value " + str(v))

It creates a set from the values , removes every element between 50 and 100 inclusive, then prints any remaining values in ascending order.

Answer 2

This avoids looping and prints a list of skipped values:

print("skipped values: " + str(values[np.isin(values, range(50, 101), invert=True)]))

numpy.isin returns values from the first argument that are in the second argument. Setting invert to True means return everything not in the second argument.