Bash：执行带引号的命令并将其输出放入变量中

Question

In a bash script I set a command this way:在 bash 脚本中，我以这种方式设置了一个命令：

getdblist_cmd=(sudo -u $backup_user $psql -p $pgsql_port -U $pgsql_user -d postgres -q -t -c 'SELECT datname from pg_database')

Then I run it with然后我运行它

dblist=`${getdblist_cmd[@]}`

I don't get any error into the bash script but the $dblist variable is empty.我没有在 bash 脚本中收到任何错误，但$dblist变量为空。

How can I execute that command and put its output into a variable?如何执行该命令并将其输出放入变量中？

Answer 1

dblist=`"${getdblist_cmd[@]}"`
        ^                   ^

The [@] operator works only correct if the ${...} is surrounded by quotes. [@]运算符仅在${...}被引号包围时才正确工作。