如何将多个列表转换为python中的字典列表？

Question

I have a program that takes 2 numbers and subtracts them and also tells us if the individual places ie ones, tens and hundreds are smaller than the number they are being subtracted from and if they need to borrow.

a=2345
b=1266
o=[int(d) for d in str(a)]
a=[int(d) for d in str(a)]
b=[int(d) for d in str(b)]
x=len(a)
y=len(b)
i=1
state=[]
c=[]
for n in range(x):
    if a[x-i]<b[y-i]:
        a[x-i]+=10
        a[x-i-1]-=1
        state.append(True)
    else:
        state.append(False)
    i+=1
i=1    
for m in range(x):
    c.append(a[x-i]-b[y-i])
    i+=1
c=c[::-1]
print(o) #before borrow
print(a) #after borrow
print(b) #number to subtract
print(c) #result
print(state) #if borrowed

And this is my output:

[2, 3, 4, 5]
[2, 2, 13, 15]
[1, 2, 6, 6]
[1, 0, 7, 9]
[False, False, False, False]

Here is my question: 1) I want to map the results to a list of dictionary for each place like below:

[{'initial_num': '5', 'after_borrow': '15', 'state': True, 'after_subtract': '9'},
{'initial_num': '4', 'after_borrow': '13', 'state': True, 'after_subtract': '7'}...]

How do I do this so that I have 4 dicts in the list each corresponding to a particular position?

Answer 1

您可以使用列表理解将您感兴趣的列表zip到dict s

l = [{'initial_num': x, 'after_borrow': y, 'state': z, 'after_subtract': k} for x, y, z, k in zip(o, a, state, c)]

Answer 2

This can achieve what you want.

a=2345
b=1266
o=[int(d) for d in str(a)]
a=[int(d) for d in str(a)]
b=[int(d) for d in str(b)]
x = len(a)
y = len(b)
i=1
state=[]
c=[]
for n in range(x):
    if a[x-i] < b[y-i]:
        a[x-i] += 10
        a[x-i-1] -= 1
        state.append(True)
    else:
        state.append(False)
    i+=1
i=1    
for m in range(x):
    c.append(a[x-i]-b[y-i])
    i += 1
c=c[::-1]
print(o) #before borrow
print(a) #after borrow
print(b) #number to subtract
print(c) #result
print(state) #if borrowed

result = []
for i in range(len(o)):
    idx = len(o) - i - 1
    result.append({
        'initial_num': o[idx],
        'after_borrow': a[idx],
        'state': state[idx],
        'after_subtract': c[idx]
    })
print(result)