如何通过文本文件进行 Python 搜索并打印每个匹配的行？

Question

Apologies for total noob question. I'm trying to learn Python. I've searched this site and have not found a solution for me. Please let me know if one has already been explained.

I'm trying to make a search program for a list of movie titles in a .txt file, and I want it to print every line that contains the words inputted by the user.

For example, if two of the lines in the text file are

22. It Happened One Night (1934)
23. Wonder Woman (2017)

and the user inputs "on" I would like both of these (and any others) to appear, since both contain the "on" at some point.

I have tried using

with open("movies.txt", "r") as f:
     searchlines = f.readlines()
for i, line in enumerate(searchlines):
    if searchphrase in line: 
        for l in searchlines[i:i+3]: print(l),
        print

but this did not work for me.

Answer 1

Something like this maybe:

with open("movies.txt", "r") as file:
    lines = file.read().splitlines()

keyword = "on"

filtered_lines = filter(lambda line: keyword.casefold() in line.casefold(), lines)

for line in filtered_lines:
    print(line)

Answer 2

You can refer snippet code bellow

def search(text_search):
    with open("movies.txt", "r") as f:
        searchlines = f.readlines()
        for i, line in enumerate(searchlines):
            # if line contains text_search we will print it
            if text_search in line:
                print(line)
if __name__ == "__main__":
    search("One")

Answer 3

def search(text_search):
    with open("movies.txt", "r") as f:
        searchlines = f.readlines()
        for i, line in enumerate(searchlines):
            if text_search.casefold() in line.casefold():
                print(line)

Example call your function with: search("ON")

Edited indentation