[英]How to Parse Json dictonary in swift 4
Hi I have a problem with this Json:嗨,我对这个 Json 有问题:
{
"id": "libMovies",
"jsonrpc": "2.0",
"result": {
"limits": {
"end": 75,
"start": 0,
"total": 1228
},
"movies": [{
"art": {
"fanart": "myfanart",
"poster": "myposter"
},
"file": "myfile",
"label": "mylable",
"movieid": mymovieid,
"playcount": 0,
"rating": myrating,
"thumbnail": "mythumbnail"
}]
}
}
When I parse Json in swift 5 with this code当我使用此代码在 swift 5 中解析 Json 时
try! JSONDecoder().decode([MyMovie].self, from: data!)
I get this error我收到这个错误
Fatal error: 'try!'致命错误:“尝试!” expression unexpectedly raised an error: Swift.DecodingError.typeMismatch(Swift.Array, Swift.DecodingError.Context(codingPath: [], debugDescription: "Expected to decode Array but found a dictionary instead.", underlyingError: nil)):表达式意外引发错误:Swift.DecodingError.typeMismatch(Swift.Array, Swift.DecodingError.Context(codingPath: [], debugDescription: "Expected to decode Array but found a dictionary 相反。",underlyingError: nil)):
How can I solve this?我该如何解决这个问题?
For the below JSON,对于下面的 JSON,
{"id":"libMovies","jsonrpc":"2.0","result":{"limits":{"end":75,"start":0,"total":1228},"movies":[{"art":{"fanart":"myfanart","poster":"myposter"},"file":"myfile","label":"mylable","movieid":"mymovieid","playcount":0,"rating":"myrating","thumbnail":"mythumbnail"}]}}
The Codable
models that you need to use,您需要使用的Codable
模型,
struct Root: Decodable {
let id, jsonrpc: String
let result: Result
}
struct Result: Decodable {
let limits: Limits
let movies: [Movie]
}
struct Limits: Decodable {
let end, start, total: Int
}
struct Movie: Decodable {
let art: Art
let file, label, movieid: String
let playcount: Int
let rating, thumbnail: String
}
struct Art: Decodable {
let fanart, poster: String
}
Parse the JSON data
like so,像这样解析JSON data
,
do {
let response = try JSONDecoder().decode(Root.self, from: data)
print(response.result.movies.map({"file: \($0.file), label: \($0.label)"}))
} catch {
print(error)
}
Edit:编辑:
To save the movies separately, create a variable of type [Movie],要单独保存电影,请创建一个类型为 [Movie] 的变量,
var movies = [Movie]()
Now, while parsing save the response.result.movies
in the above created property,现在,在解析时将response.result.movies
保存在上面创建的属性中,
do {
let response = try JSONDecoder().decode(Root.self, from: data)
print(response.result.movies.map({"file: \($0.file), label: \($0.label)"}))
movies = response.result.movies
} catch {
print(error)
}
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