如何使用 if 函数作为 try except

Question

I have a program which has a loop in it. In this loop I load images from a file. But there are some not usable images, that I don`t want to sort by hand. I have this code:

        img = Image.open("downloads/parrot/" + pictures[i])
        img = img.resize((150,150))
        img.save("Validation/parrot/" + "picture" + str(i) + ".png")
        i = i + 1

I tried to use the try except method, but it always stopped the program. Is there any way to use an if loop, like "if imageisuseful() = false:"? Or do you may have any other Ideas? Thank you for your help.

Answer 1

If you don't want your try / except to stop your code, you can pass :

try:
    img = Image.open("downloads/parrot/" + pictures[i])
    img = img.resize((150,150))
    img.save("Validation/parrot/" + "picture" + str(i) + ".png")
    i = i + 1
except:
    pass # pictures[i] raised an exception here

Answer 2

Depending on where the error is happening (either at the open or the resize) you might need to move things around:

img = Image.open("downloads/parrot/" + pictures[i])
try:
    img = img.resize((150,150))
    img.save("Validation/parrot/" + "picture" + str(i) + ".png")
    i = i + 1
except:
    print("FILE {} DOESN'T WORK".format(pictures[i]))