在Android Studio中获取数组中两个字符串之间的所有字符串

Question

I'm looking for a way to grab all the strings between two strings in an array.

String[] list = inputOCR.split("(?=\\p{Space})"); = this is the way I built the array.

The order of the strings goes like [Other,Name, Middle, First, Last,Address, word, word, word, word, word, word, License, etc, etc, etc, etc] How do I get all the words between address and license inside the array?

Update: The index of the array isnt fixed based on the OCR scan,so I also have to look for the word "Address", and "License" in the array.

Answer 1

Ah yes, indexes can be confusing! I've got some code that might help you along. What you want to do, once you've split the words into an array, is find the index (position) of the words that are the start and end of your search. In this case, "address" and "license". Then you can loop between these values to get the words you need.

public class GetWords {

    public static void main(String[] args) {
        String inputOCR = "This contains some address random words used to test License should not be picked up";
        String[] list = inputOCR.split(" "); 

        int startPosition = getIndexOfWordInArray(list, "address") + 1;
        int endPosition = getIndexOfWordInArray(list, "license");

        for (int i = startPosition; i < endPosition; i++) {
            System.out.println(list[i]);
        }
    }

    public static int getIndexOfWordInArray(String[] list, String word) {
        int index = -1;

        for (int i = 0; i < list.length; i++) {
            if (list[i].equalsIgnoreCase(word)) {
                index = i;
                break;
            }
        }

        return index;
    }
}

The code above splits the string on spaces, then gets the positions of "address" and "license" from the index. It then loops through the array, printing the words between those two positions. The code adds 1 to the position of "address", because you want to exclude it and it stops just before the position of "license".

Instead of printing the words, you can add them to an ArrayList, which is an array that can grow dynamically, depending on how much you put into it.

I tried to keep the code as simple and beginner-friendly as possible, but please ask if it's still unclear.

Answer 2

Ok if I got you right, I hope I did, this should do the trick:

// Code begins with a splitted array so String[] list exists already
int address = 0; // this will determine where your Address is located in the array
int license = -1; // this will determine where license is located in the array

for (int i = 0; i < list.length; i++) {
    if (list[i].equals("Address"))
        address = i;
    else if (address != 0 && list[i].equals("License")) {
        license = i;
        break;    // loop can be left as everything else is unimportant
    }
}

String[] result = new String[license-address-1]; // This will throw an error on purpose if license and/or address were not in list
for (int i = address+1; i < license; i++)
    result[i-address-1] = list[i]; // actual copying
// Be happy with your result String[]