我怎样才能让 CMFCButton 看起来像一个标准的复选框？

Question

A standard MFC CButton checkbox on a color background looks like this:

I want to get rid of the gray margin, but can't get it to go away. No matter how I set the size of the control it still appears.

Changing it to an CMFCButton gives this:

Which is good, it gets rid of the margin, except now there's no checkmark. I need that checkmark.

Is there any way to get the clean appearance with the checkmark? I had the thought of passing the standard set of images to CMFCControl::SetImage() , but I don't see how to get them. I know I can draw everything myself, but I'm trying to avoid reinventing the wheel.

I know there are many similar questions here on SO, but none of the answers I found seem to apply. The closest I found was this: Once and for all: how do I get a fully transparent checkbox, button, radio button, etc. in Windows API, and not with a black background? ; but the first answer there is very cryptic, and the second is a big chunk of code that seems like overkill.

Answer 1

I found something simple that worked:

After adding ON_WM_CTLCOLOR() to the dialog's MESSAGE_MAP , I added this to the dialog class:

HBRUSH MyDlg::OnCtlColor(CDC* pDC, CWnd* pWnd, UINT nCtlColor)
{
    HBRUSH hbr = CDialogEx::OnCtlColor(pDC, pWnd, nCtlColor);

    if (myCheckbox.m_hWnd == pWnd->m_hWnd) // myCheckbox is the problem control
    {
        pDC->SetBkMode(TRANSPARENT);
        hbr = reinterpret_cast<HBRUSH>(::GetStockObject(NULL_BRUSH));
    }

    return hbr;
}