[英]Making each column of each DataFrame in a list into its own list within a big list
Task Description任务描述
If I have a list of DataFrames in say a_list
and each list looked like the following:如果我在a_list
有一个 DataFrame 列表,并且每个列表如下所示:
1 2 3
a x x x
b y y y
c z z z
I am interested in making each column of each DataFrame in a_list
into its own list.我有兴趣将a_list
中每个 DataFrame 的每一列都放入自己的列表中。
So say b_list[0]
would be所以说b_list[0]
将是
1
a x
b y
c z
b_list[1]
would be b_list[1]
将是
2
a x
b y
c z
etc.等等。
I currently have around 150 DataFrames in a list with each having 30+ columns.我目前在一个列表中有大约 150 个数据帧,每个数据帧有 30 多列。 So the desired list would have around b_list[4500]
Any help with this would be awesome!所以所需的列表大约有b_list[4500]
任何有关此的帮助都会很棒!
Try this:尝试这个:
b_list = []
for df in a_list:
for col in df.columns:
b_list.append(df[[col]])
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