[英]fetch the associative array particular value with its key name
i have a function .我有一个功能。 here i am passing an array applicationTabId = {"twitter": "15", "dropbox": "14"};
在这里我传递一个数组 applicationTabId = {"twitter": "15", "dropbox": "14"}; "}; I have an ajax success function .In this the variable appName name holds the key names as twitter , dropbox etc. I got this from database as ajax response. i want to find the value associated with this from the array. variable appName holding the key names and iam getting it from database as ajax response. i need to check the corresponding value of this name from array.
"}; 我有一个 ajax 成功函数。在这个变量 appName 名称中保存关键名称为 twitter、dropbox 等。我从数据库中作为 ajax 响应得到它。我想从数组中找到与此相关的值。变量 appName保存键名并从数据库中获取它作为 ajax 响应。我需要从数组中检查此名称的相应值。
function getapplicationlogouturl(applicationTabId) {
chrome.storage.sync.get("endpoint", function (obj) {
FetchLogoutUrl = {
"applicationName": applicationTabId,
"sdcode": sdcode,
"type": "Chrome Fetch Application Logout Url"
};
$.ajax({
type: "POST",
url: obj.endpoint,
dataType: "json",
data: JSON.stringify(FetchLogoutUrl),
context: document.body,
timeout: globalTimeout,
success: function (response) {
if (response != null ) {
for (var i = 0; i < response.length; i++) {
var appName = response[i].name;
console.log(applicationTabId);
// o/p as {"twitter": "15", "dropbox": "14"}
console.log(appName);
//o/p as twitter
//dropbox
var tabid = applicationTabId.appName;
//var tabid = applicationTabId[appName];
console.log(tabid);
//o/p as undefined
console.log(appName+'---'+tabid);
if (appName in applicationTabId){
}
}
}
},
});
});
}
Apply loop like below:应用循环如下:
$.each(applicationTabId, function(key,value){
console.log(key);
console.log(value);
});
Based on code you provided now, change your code like below:根据您现在提供的代码,更改您的代码,如下所示:
function getapplicationlogouturl(applicationTabId) {
FetchLogoutUrl = {
"applicationName": applicationTabId,
};
$.ajax({
type: "POST",
url: obj.endpoint,
dataType: "json",
data: JSON.stringify(FetchLogoutUrl),
context: document.body,
success: function (response) {
if (response != null ) {
for (var i = 0; i < response.length; i++) {
var appName = response[i].name;
var tabid = applicationTabId[appName];
//print key value data in console to check working fine
console.log(appName+'---'+tabid);
}
}
},
});
}
Note:- var appName
and var tabid
value will be changed after each iteration happen.注意:-
var appName
和var tabid
值将在每次迭代发生后更改。
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