[英]Extract record from dictionary list where key and value does not contains given value list c#
List<Dictionary<string, string>> firstList = new List<Dictionary<string, string>>();
Dictionary<string, string> dict = new Dictionary<string,string>();
dict.Add("name", "abc");
dict.Add("age", "22");
dict.Add("address", "xyz,aa");
dict.Add("contact", "111");
firstList .Add(dict);
Dictionary<string, string> dict2 = new Dictionary<string,string>();
dict2 .Add("name", "pqr");
dict2 .Add("age", "25");
dict2 .Add("address", "xxx,bb");
dict2 .Add("contact", "4222");
firstList .Add(dict2);
Dictionary<string, string> dict3 = new Dictionary<string,string>();
dict3 .Add("name", "aa");
dict3 .Add("age", "24");
dict3 .Add("address", "xxx,aa");
dict3 .Add("contact", "aaa");
firstList .Add(dict3);
return record where list doesn't not contains key = 'address' and name= 'aa'返回列表不包含 key = 'address' 和 name = 'aa' 的记录
Update :- return record where name= 'aa'更新:- 返回记录,其中名称 = 'aa'
Pretty simple with linq:使用 linq 非常简单:
var result = firstList.Where(x => !(x.ContainsKey("address")
&& x.ContainsKey(name)
&& x["name"] == "aa")).ToList();
and if only one record is required back then use FirstOrDefault()
:如果只需要一条记录,则使用FirstOrDefault()
:
var result = firstList.Where(x => !(x.ContainsKey("address")
&& x.ContainsKey(name)
&& x["name"] == "aa")).FirstOrDefault();
Don't forget to add on top:不要忘记在上面添加:
using System.Linq;
var result = firstList.Where(x =>
&& x.ContainsKey(name)
&& x["name"] != "aa")).FirstOrDefault();
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