[英]Type hinting a list with coupled inheritance
I'm using Python 3.7.6 with PyCharm.我在 PyCharm 中使用 Python 3.7.6。 I want my code to work as a nice internal API with code completion appearing for objects so I want to use typing.
我希望我的代码作为一个很好的内部 API 工作,并为对象显示代码完成,所以我想使用输入。
I'm trying to find a good pattern for when:我正在尝试为以下情况找到一个好的模式:
(example below) (下例)
I've found a way below but it feels like a hack.我在下面找到了一种方法,但感觉就像一个黑客。 What's the right (or better) way to do this?
这样做的正确(或更好)方法是什么?
from typing import List, Type
class Leg:
def step(self):
print("step")
class DuckLeg(Leg):
def paddle(self):
print("splosh")
class Biped:
def __init__(self, leg_type: Type[Leg]):
self.legs: List[leg_type] = [leg_type(), leg_type()]
def walk(self):
for leg in self.legs:
leg.step()
class Duck(Biped):
def __init__(self):
super().__init__(leg_type=DuckLeg)
self.legs: List[DuckLeg] = self.legs # A hack?
my_duck = Duck()
my_duck.walk() # code-completion appears for .walk()
my_duck.legs[0].paddle() # code-completion appears for .paddle()
Edit 1: This question is not about where to put the type annotations but how to ensure code-completion works in this context.编辑 1:这个问题不是关于在哪里放置类型注释,而是如何确保代码完成在这种情况下工作。 If the following line is commented-out...
如果以下行被注释掉...
self.legs: List[DuckLeg] = self.legs
...the code will still run because of duck-typing but code-completion will not appear for .paddle() and when manually entered PyCharm code inspection will report: Unresolved attribute reference 'paddle' for class 'Leg'. ...由于鸭子输入,代码仍将运行,但 .paddle() 不会出现代码完成,当手动输入 PyCharm 代码检查将报告:未解析的属性引用 'Leg' 类的属性引用 'paddle'。
Not sure if this actually solves your problem but I think it's cleaner than what you propose:不确定这是否真的解决了您的问题,但我认为它比您提出的更清晰:
from typing import List, Type
class Leg:
def step(self):
print("step")
class DuckLeg(Leg):
def paddle(self):
print("splosh")
class Biped:
LegType = Leg
def __init__(self):
# self.LegType always gives the correct leg type for the instance
self.legs: List[self.LegType] = [self.LegType(), self.LegType()]
def walk(self):
for leg in self.legs:
leg.step()
class Duck(Biped):
LegType = DuckLeg
def __init__(self):
super().__init__()
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