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oracle中基于列值的JOIN表

[英]JOIN Tables based on the column value in oracle

I'm trying to join a table based on the column values like (A&B)||(C&D) .我正在尝试根据(A&B)||(C&D)等列值加入一个表。 I can create a join for A&B and C&D separately.我可以分别为 A&B 和 C&D 创建一个连接。 But how will I accomplish the OR condition in between?但是我将如何完成两者之间的OR条件?

[UPDATE] A, B, C and D are the level_ids in dummy_level table. [更新] A、B、C 和 D 是 dummy_level 表中的 level_id。 So the ground rule for joining the table is (21 && 22) ||所以加入表格的基本规则是 (21 && 22) || (23 && 24) (23&&24)

My table structure is,我的表结构是,


CREATE TABLE dummy_cust(
  id INT,
  NAME VARCHAR(50),
  age INT,
  country VARCHAR(50));

INSERT INTO dummy_cust VALUES (1,'KIM',23,'US');
INSERT INTO dummy_cust VALUES (2,'KOM',24,'US');
INSERT INTO dummy_cust VALUES (3,'KING',29,'US');
INSERT INTO dummy_cust VALUES (4,'RAM',29,'US');
INSERT INTO dummy_cust VALUES (5,'RAV',23,'US');
INSERT INTO dummy_cust VALUES (6,'KIV',25,'US');

CREATE TABLE dummy_level(
  id INT,
  level_id INT,
  STATUS VARCHAR(50));

INSERT INTO dummy_level VALUES (1,21,'C');
INSERT INTO dummy_level VALUES (1,22,'C');
INSERT INTO dummy_level VALUES (1,24,'C');
INSERT INTO dummy_level VALUES (2,22,'C');
INSERT INTO dummy_level VALUES (2,23,'C');
INSERT INTO dummy_level VALUES (2,24,'C');
INSERT INTO dummy_level VALUES (3,21,'Z');
INSERT INTO dummy_level VALUES (3,22,'Z');
INSERT INTO dummy_level VALUES (4,21,'Z');
INSERT INTO dummy_level VALUES (4,22,'Z');
INSERT INTO dummy_level VALUES (4,24,'Z');

Expected Result:预期结果:


+ --- + ---- + --- + ------- + -------- + ------- + -------- + ------- + -------- + ------- + -------- + ------- +
| id  | name | age | country | Level ID | Status  | Level ID | Status  | Level ID | Status  | Level ID | Status  |
+ --- + ---- + --- + ------- + -------- + ------- + -------- + ------- + -------- + ------- + -------- + ------- +
| 1   | KIM  | 23  | US      | 21       | C       | 22       | C       |          |         | 24       | C       |
| 2   | KOM  | 24  | US      |          |         | 22       | C       | 23       | C       | 24       | C       |
| 3   | KING | 29  | US      | 21       | Z       | 22       | Z       |          |         |          |         |
| 4   | RAM  | 29  | US      | 21       | Z       | 22       | Z       |          |         | 24       | Z       |
+ --- + ---- + --- + ------- + -------- + ------- + -------- + ------- + -------- + ------- + -------- + ------- +


Please help to solve this.请帮助解决这个问题。 Slightly handicapped as I'm new to this.因为我是新手,所以有点残疾。 I badly need the experts to help here in solving this.我非常需要专家在这里帮助解决这个问题。

You are pivoting some values, so easiest is to join and use pivot :您正在旋转一些值,因此最简单的方法是加入和使用pivot

select *
  from dummy_cust c 
  join dummy_level  l using (id)
  pivot (max(level_id) lvl, max(status) sts 
         for level_id in (21 as l21, 22 as l22, 23 as l23, 24 as l24) )
  order by id         

dbfiddle demo dbfiddle 演示

If I understand your comment correctly, you want to show rows when they have both levels 21 and 22 or both levels 23 and 24. So:如果我正确理解您的评论,您希望在它们同时具有 21 和 22 级或同时具有 23 和 24 级时显示行。所以:

select *
  from (
    select c.id, c.name, c.age, c.country, l.level_id, l.status,
           count(case level_id when 21 then 1 end) over (partition by c.id) c21,
           count(case level_id when 22 then 1 end) over (partition by c.id) c22,
           count(case level_id when 23 then 1 end) over (partition by c.id) c23,
           count(case level_id when 24 then 1 end) over (partition by c.id) c24
      from dummy_cust c 
      join dummy_level l on c.id = l.id )
  where (c21 > 0 and c22 > 0) or (c23 > 0 and c24 > 0)

Then you can make pivot for presentation.然后,您可以制作用于演示的枢轴。

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