如何在 PHP 中使用 file_get_contents 从变量中回显

Question

I am trying to echo the contents of a .php file using file_get_contents.

The filename of which the content is supposed to be echoed from is generated partly by a sql query as below:

$property_info = '"include/textfiles/' . $properties['expose_info'] . '_info.php"';

I am then trying to do echo file_get_contents($property_info);

For some reason this is not working, but if i'm doing echo $property_info; it is outputting the correct file path and when i copy paste that file path back into file_get_contents its also echoing the file contents just how i want it.

So whats the reason for echo file_get_contents($property_info); not working? No variables allowed?

Answer 1

Use

$property_info = 'include/textfiles/' . $properties['expose_info'] . '_info.php';

Not

$property_info = '"include/textfiles/' . $properties['expose_info'] . '_info.php"';

Reason :

Your $property_info contain double qoute inside single quote