如何通过 Sendmail 邮寄命令输出

Question

I want to cron a simple commandline output via the standard linux sendmail function (using Centos).

The command is: ll -rt | grep error ll -rt | grep error This will give me a list of error log files.

I want the solution as simple as possible, can I do something like sendmail user@example.com < ll -rt | grep error sendmail user@example.com < ll -rt | grep error . Or is there a more elegant way?

Btw, this gives me an error output: bash: ll -rt | grep error: No such file or directory bash: ll -rt | grep error: No such file or directory

Thanks for your insights.

Answer 1

Use a pipe:

ll -rt | grep error | sendmail user@example.com

< is for redirection from a file, not a command, so it's trying to read from the file named ll .

You obviously already know about pipelines, since you used it to pipe the output of ls to grep .