通过多个分隔符拆分字符串并保留一些分隔符而丢弃其他分隔符

Question

I would like to split by the space string " " while removing it and also split by a comma "," while keeping it.

var str = "This is a word, and another."
var regexKeepCommaDelimeter = new RegExp(/(,)/,'g')
var regexKeepCommaRemoveSpace = new RegExp(/(????)/,'g')
var splitArray = str.split(regexKeepCommaRemoveSpace)
var desiredArray = ['This', 'is', 'a', 'word', ',', 'and', 'another.' ]
var testPassed = splitArray.every((x,i)=> x == desiredArray[i])
console.log('Arrays match:', testPassed)

Answer 1

One fairly simple approach would be to add spaces around any , that don't have them, then just split on space:

var splitArray = str.replace(/ ?, ?/g, " , ").split(" ");

Live Example:

 var str = "This is a word, and another." var splitArray = str.replace(/ ?, ?/g, " , ").split(" "); console.log(splitArray); var desiredArray = ['This', 'is', 'a', 'word', ',', 'and', 'another.' ]; console.log(splitArray.every((e, i) => e === desiredArray[i]));

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Answer 2

Match the space, and match and capture the comma when splitting with str.split(/\\s+|(,)/).filter(Boolean) .

Or, you may match any amount of chars other than whitespace and commas, or just a comma with str.match(/[^\\s,]+|,/g) .

 var str = "This is a word, and another."; console.log( str.split(/\\s+|(,)/).filter(Boolean) ); // => ["This", "is", "a", "word", ",", "and", "another."] console.log( str.match(/[^\\s,]+|,/g) ); // => ["This", "is", "a", "word", ",", "and", "another."]

The .filter(Boolean) part will remove empty items from the resulting array that appear due to eventual consecutive matches, or matches at the start of the string.