PHP MySQL 查询 2 个数据表并组合成一个 json 数组以进行回显？

Question

How to combine these 2 queries into one php array that echos back to ajax request in json format? Each statement is confirmed working alone.
Something that looks like:

 'fname' => $fname,
 'lname' => $lname,
'gender' => $gender,
  'city' => $city,
 'state' => $state
   'bio' => $bio

PHP MySQL request

<?php
include 'sqlconnection.php';
$conn = OpenCon();

$stmt = $conn->prepare('SELECT fname,lname,gender,city,state FROM users WHERE uid='.$_POST['info']);
$stmt->execute();
$stmt->bind_result($fname,$lname,$gender,$city,$state);
while($stmt->fetch()) {
    $output=array(
        'fname' => $fname,
        'lname' => $lname,
        'gender' => $gender,
        'city' => $city,
        'state' => $state
    );
}
$json=json_encode($output);
echo $json;

$stmt = $conn->prepare('SELECT bio FROM profile WHERE uid='.$_POST['info']);
$stmt->execute();
$stmt->bind_result($bio);
while($stmt->fetch()) {
    $output=array(
        'bio' => $bio
    );
}
$json=json_encode($output);
echo $json;

$stmt->close();
CloseCon($conn);
?>

Answer 1

You can simply JOIN your two tables on uid to merge the two queries into one. Note you are not using prepared statements properly, you should put in a placeholder for uid and then use bind_param to attach a value:

$stmt = $conn->prepare('SELECT u.fname,u.lname,u.gender,u.city,u.state,p.bio
                        FROM users u
                        JOIN profile p ON p.uid = u.uid
                        WHERE u.uid=?');
$stmt->bind_param('s', $_POST['info']);
$stmt->execute();
$stmt->bind_result($fname,$lname,$gender,$city,$state,$bio);
while($stmt->fetch()) {
    $output=array(
        'fname' => $fname,
        'lname' => $lname,
        'gender' => $gender,
        'city' => $city,
        'state' => $state,
        'bio' => $bio
    );
}

Note that if it's possible a user will not have an entry in the profile table, you should use a LEFT JOIN instead of a JOIN .