如何使用流从双精度数组中过滤掉非整数值？

Question

IntelliJ has been telling me that the Double[] is an error: bad return type in method reference: cannot convert Double[] to A[]. I have used double[], removed the ::new static reference, and still the same error. How do I resolve this error? I am attempting to get back 1.000 in the filtered results.

double[] pricesDoubleArr = {1.000,2.800,4.900};
double[] pricesDoubleFiltered = Arrays.stream(pricesDoubleArr)
                                      .filter(x -> x != Math.round(x))
                                      .toArray(Double[]::new);

Answer 1

Just use .toArray(); without Double[]::new , because your stream hold from beginning an array of double:

double[] doubles = Arrays.stream(pricesDoubleArr)
        .filter(x -> x != Math.round(x))
        .toArray();

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I'm not sure what are you looking from your code, but from your question:

I am attempting to get back 1.000 in the filtered results.

I think you are looking to:

.filter(x -> x == (double) (int) x)