根据第二列中存在的字符串更新第一列

Question

I want to update price 2 times if there is "buy 1 get 1 50%" and 3 times if "buy 1 get 1 40%"

1. Price| Special_Offer
2. 330 |BUY 1 GET 1 50%
3. 810 | BUY 1 GET 1, 40%
4. 210 |BUY 1,GET 1 at 50%

Below is my code, but it is not working

DF["Price"]=np.where(DF["Special Offer"].str.contains(r"(BUY 1)(GET1)(50%)",case=False,regex=True),DF["Price]*2,DF["Price])

Answer 1

You forgot the spaces in between, and also dont group with brackets. As I undestand you want to capture the price. So we capture it with \\d+ and check if there are needed context with a lookahead like (?= \\| BUY 1 GET 1 50%)

\d+(?= ?\| ?BUY 1[, ] ?GET 1(?:,? ?| at )50%)
\d+(?= ?\| ?BUY 1[, ] ?GET 1(?:, ?| at )40%)

demo

https://regex101.com/r/vG1kzW/3

https://regex101.com/r/QImMZf/2

Answer 2

this one is working.

\d+(?= ?\| ?BUY 1[, ] ?GET 1(?:,? ?| at )50%)
\d+(?= ?\| ?BUY 1[, ] ?GET 1(?:, ?| at )40%)