.str.contains 方法中的操作 AND

Question

i have toy dataframe

toy_df = pd.DataFrame({'col1': ["apple is green",
                       "banana is yellow",
                       "strawberry is red"],
                     'col2': ["dog is kind",
                       "cat is smart",
                       "lion is brave"]})

with output:

                 col1           col2
0      apple is green     dog is kind
1    banana is yellow    cat is smart
2   strawberry is red   lion is brave

i have two targets to search, where first is

apple or lion and second one is brave :

target = 'apple|lion' target2 = 'brave'

i can search with first target easily:

toy_df[toy_df.apply(lambda x: x.str.contains(targets)).any(axis=1)]

outpus is:

                 col1            col2
0      apple is green     dog is kind
2   strawberry is red   lion is brave

but how i shoud search with TWO targets ( target1 and target2 ) ? to get this output:

                 col1            col2
2   strawberry is red   lion is brave

Answer 1

Use logical AND ( & ) to combine both boolean conditions:

Example

mask1 = toy_df.apply(lambda x: x.str.contains(targets)).any(axis=1)
mask2 = toy_df.apply(lambda x: x.str.contains(target2)).any(axis=1)

toy_df[mask1 & mask2]

[out]

                col1           col2
2  strawberry is red  lion is brave

---

Update - full code

toy_df = pd.DataFrame({'col1': ["apple is green",
                       "banana is yellow",
                       "strawberry is red"],
                     'col2': ["dog is kind",
                       "cat is smart",
                       "lion is brave"]})

targets = 'apple|lion'
target2 = 'brave'

mask1 = toy_df.apply(lambda x: x.str.contains(targets)).any(axis=1)
mask2 = toy_df.apply(lambda x: x.str.contains(target2)).any(axis=1)

toy_df[mask1 & mask2]