JavaScript 返回函数不是 true 结果

Question

I have an array and a function checkMember. I want to check, do the member have in the array? But checkMember function only true if I call checkMember('Cody'). I don't understand. Please help me!

var fe01 = [
  {name: 'Giang', fee: 5, fea: 6},
  {name: 'Zack', fee: 7, fea: 7},
  {name: 'Henry', fee: 8, fea: 8},
  {name: 'Cody', fee: 9, fea: 9}
];    

function checkMember(name){
  var result;
  for(var i = 0; i < fe01.length; i++){
     console.log(`${fe01[i].name}`)
     if(fe01[i].name == name){
       //console.log(true);
       result = true;
     } else{
       //console.log(false)
       result = false;
     }
  }     
  return result;
}

console.log(checkMember('Cody'));//true
console.log(checkMember('Giang'));//false

Answer 1

There are many ways to solve this.

Using for..loop with break statement:

 var fe01 = [ {name: 'Giang', fee: 5, fea: 6}, {name: 'Zack', fee: 7, fea: 7}, {name: 'Henry', fee: 8, fea: 8}, {name: 'Cody', fee: 9, fea: 9} ]; function checkMember(name){ var result; for(var i = 0; i < fe01.length; i++){ //console.log(`${fe01[i].name}`) if(fe01[i].name == name){ //console.log(true); result = true; break; // jump out of the loop here } else{ //console.log(false) result = false; } } return result; } console.log(checkMember('Cody'));//true console.log(checkMember('Giang'));//true

Using some() method:

 var fe01 = [ {name: 'Giang', fee: 5, fea: 6}, {name: 'Zack', fee: 7, fea: 7}, {name: 'Henry', fee: 8, fea: 8}, {name: 'Cody', fee: 9, fea: 9}]; function checkMember(search){ return fe01.some(({name}) => name == search); } console.log(checkMember('Cody'));//true console.log(checkMember('Giang'));//true console.log(checkMember('abc'));//false

Answer 2

This will work for you.

    var fe01 = [
            {name: 'Giang', fee: 5, fea: 6},
            {name: 'Zack', fee: 7, fea: 7},
            {name: 'Henry', fee: 8, fea: 8},
            {name: 'Cody', fee: 9, fea: 9}
        ];

function checkMember(name){
            return fe01.some(obj => obj.name == name)
        }

console.log(checkMember('Cody'));//true
console.log(checkMember('personX'));//false