转换向量<std::unique_ptr<A> &gt; 到矢量

Question

There is a vector of std::unique_ptr<A> . I need to pass that data to a function that expects a vector of A .

I tried using std::transform , like this:

std::vector<std::unique_ptr<A>> a;

std::vector<A> aDirect;
std::transform(a.begin(), a.end(),
    std::back_inserter(aDirect),
    [](std::unique_ptr<A> element)-> A { return *element; });

but it seems that std::transform tries to copy elements of a at some point, so that doesn't work, it fails as trying to reference a deleted function.

Of course, I could just do it manually with a for loop, but I was wondering if there was a more elegant way of doing it.

Answer 1

change the lambda to take a const &

[](std::unique_ptr<A> const &element)-> A { return *element; });

to avoid copies due to resizing reserve correct size before transforming.

std::vector<A> aDirect;
aDirect.reserve(a.size());
std::transform(a.begin(), a.end(),
               std::back_inserter(aDirect),
               [](std::unique_ptr<A> element) {
                   return *element;
               });