[英]After flattening a Java 8 multilevel map my expected result is empty
I have the below multilevel map:我有以下多级地图:
Map<String, List<Map<String, Map<String, Map<String, Map<String, String>>>>>> input =
ImmutableMap.of("A",
ImmutableList.of(ImmutableMap.of("2",
ImmutableMap.of("3",
ImmutableMap.of("4",
ImmutableMap.of("5", "a"))))));
In short it'll be like总之它会像
{
"A":[{"2":{"3":{"4":{"5":"a"}}}}],
"B":[{"2":{"3":{"4":{"5":"b"}}}}]
}
My requirement is to construct a map of the form我的要求是构造一张表格的地图
{
"A":"a",
"B":"b"
}
I tried the below code but for some reason myMap
is always empty even though I'm populating it.我尝试了下面的代码,但由于某种原因,即使我正在填充它,
myMap
也始终为空。 What am I missing?我错过了什么?
Map<String, String> myMap = new HashMap<>();
input.entrySet()
.stream()
.map(l -> l.getValue().stream().map(m -> m.get(m.keySet().toArray()[0]))
.map(n -> n.get(n.keySet().toArray()[0]))
.map(o -> o.get(o.keySet().toArray()[0]))
.map(p -> myMap.put(l.getKey(), p.get(p.keySet().toArray()[0])))).collect(Collectors.toList());
System.out.println(myMap);
Here's what I get when I add two peek
calls to your pipeline:这是我在管道中添加两个
peek
调用时得到的结果:
input.entrySet().stream()
.peek(System.out::println) //<- this
.map(l -> ...)
.peek(System.out::println) //<- and this
.collect(Collectors.toList());
output:输出:
A=[{2={3={4={5=a}}}}]
java.util.stream.ReferencePipeline$3@d041cf
If you notice the problem, you're collecting streams, and these streams don't get executed through a call to a terminal operation... When I try adding something like .count()
to the inner stream, your expected output is produced:如果你注意到这个问题,你正在收集流,并且这些流不会通过调用终端操作来执行......当我尝试将
.count()
类的东西添加到内部流时,会产生预期的输出:
...
.map(l -> l.getValue().stream().map(m -> m.get(m.keySet().toArray()[0]))
.map(n -> n.get(n.keySet().toArray()[0]))
.map(o -> o.get(o.keySet().toArray()[0]))
.map(p -> myMap.put(l.getKey(), p.get(p.keySet().toArray()[0])))
.count()) //just an example
...
Now, I suppose you know that a terminal operation needs to be called for the intermediate ones to run.现在,我想您知道需要调用终端操作才能运行中间操作。
In a rather desperate attempt to simplify this code, as the stream seems to make it simply hard to read, I thought you might be interested in this, which assumes that no collection is empty in the tree but at least addrsses the record as one object, and not a collection of records (but I'm sure no code will look clean for that deep map of of maps).在简化此代码的相当绝望的尝试中,由于流似乎使其难以阅读,我认为您可能对此感兴趣,它假设树中没有集合是空的,但至少将记录添加为一个对象,而不是记录的集合(但我敢肯定,对于地图的深层地图,没有代码看起来很干净)。
String key = input.keySet().iterator().next();
String value = input.entrySet().iterator().next()
.getValue().get(0)
.values().iterator().next()
.values().iterator().next()
.values().iterator().next()
.values().iterator().next();
myMap.put(key, value);
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