打字稿将对象转换为忽略属性的类

Question

I have an object that I am trying to cast from my webapi call.

So lets say this is the data from the webapi

let userTestStatus: { id: number, name: string }[] = [
    { "id": 0, "name": "Available", "date" : "01/01/2001" },
    { "id": 1, "name": "Ready", "date" : "01/01/2001" },
    { "id": 2, "name": "Started", "date" : "01/01/2001" }
];

This is my typescript Class. As you can see there is no date property

export myClass{
  id: number;
   name: string;
}

When the object is converted the date property is there even though it doesn't exist in my class. How can I get typescript to ignore properties that do not exist in the class?

Answer 1

You can map all of your objects just to such model which you would like to have

const myModelObejctsArray: MyModel[] = userTestStatus.map(user => {
   return {
    id: user.id,
    name: user.name
   }
})

Answer 2

Your data fulfills the given type interface. However, your data has even more properties than you declared as a type.

Your Typescript IDE should display you some message that the objects in your array do not specifically have a date property. But you can still run it.

If you do not want the date property in your array elements, you could delete it on your own:

userTestStatus.forEach(e => delete e.date);