在 bash 中使用正则表达式列出文件 | 忽略具有某些字符的文件

Question

I am new to regex, I want to list file matching with given regex. I have some samples files as shown in below picture

I want regex which should return below mentioned files:

test1.csv test2.csv test3.csv test9.csv.tt

I want to use the find command for this and i also tried with below mentioned find command but could not achive my expected results

find . -maxdepth 1 -type f -name "**test[0-9]*[^-a-zA-Z_]***.csv*" -exec ls -l {} +

I want to use same commnad to achieve my expected output only i want correct regex.

Anyone have any idea please do help!

Answer 1

Using find , you can try:

find . -type f -regex ./test[0-9]\\*.csv.\\* -exec ls -l {} +

Or, using sed , you can try

$ ls -l | sed '/^d/d;/ test[0-9]*\\.csv.*/!d'

(not sure if digits are mandatory -- if they're, then replace * by + )

There are 2 commands in this sed .

1. /^d/d deletes any row that starts with a d (exclude directories)
2. / test[0-9]*\\.csv.*/!d removes any row that doesn't match the regex you want to filter by.