Python 函数字典调用每个函数

Question

This seems very trivial but for some reason my dictionary is not working.

This is the code I have:

class Calculator():
    def __init__(self):
        number = input()
        self.switch_case(number)

    def switch_case(self, number):
        switcher = {
            1: self.one(),
            2: self.two(),
        }

    def one(self):
        print("something")

    def two(self):
        print("something")

For some reason this calls both functions one() and two() even when I only enter the value 1 as an input.

Answer 1

Actually it calls nothing. Your code as presented is never run.

But if you would create a Calculator instance, __init__ is run which then runs switch_case and initializes the dictionary by evaluating the value expressions. This will call both functions.

If you don't want to run them at this point, remove the parentheses:

switcher = {
        1: self.one,
        2: self.two,
        }

and call the function when needed, with something like:

self.switcher[1]()

Note the () which will do the call.

Answer 2

当您创建字典，第一，这些方法被称为=这就是为什么你看到的东西两次，然后值被从方法返回被分配到字典（在这种情况下没有，原因仅方法打印，没有返回）。