这是什么类型的函数（带代码的指针函数）？

Question

This is the first time I am seeing something like this where a function is like a pointer (but it is not a function pointer ??). See example below.

static struct test *MyFunc(struct astr *A, int count)
{

}

MyFunc(B, 100);

Can someone explain how the above works as well as why you would use a pointer function (if that is the correct term) as well as why not simply use

 static struct test MyFunc(struct astr *A, int count)

Answer 1

可以这样想：

static (struct test *) MyFunc(struct astr *A, int count)

Answer 2

So let's look at the function declaration:

static struct test *MyFunc(struct astr *A, int count)

The function itself is static (Local to the file it was declared in), and returns a pointer (Location in memory) to a value with a struct test type. In other words, it is a static function with return type struct test * .

Remember: Static function declarations specify the storage class of the function itself , not the return type .