[英]Function to return values in dictionary
This is my dictionary:这是我的字典:
seven_segment = {'0': {'a','c','d','e','b','f'},
'1': {'c','b'},
'2': {'a','d','e','b','g'},
'3': {'a','c','d','b','g'},
'4': {'g','c','f','b'},
'5': {'a','c','d','g','f'},
'6': {'a','c','d','e','g','f'},
'7': {'a','c','b'},
'8': {'a','c','d','e','b','g','f'},
'9': {'a','c','d','b','g','f'}}
I have a function created:我创建了一个函数:
def guess_damaged(display, state, damaged):
sorted_state = ''.join(sorted(state))
sorted_damaged = ''.join(sorted(damaged))
for key in display:
templist = list(display[key])
templist = sorted(templist)
templist = ''.join(templist)
if(templist == sorted_state):
return {key for key,value in display.items() if all(sorted_damaged in value for sorted_damaged in sorted_state)}
print(guess_damaged(seven_segment, 'adeg', 'bf'))
print(guess_damaged(seven_segment, 'abed', 'cf'))
print(guess_damaged(seven_segment, '', 'abcdefg'))
My current output is shown below:我当前的输出如下所示:
None
None
None
However, this is my desired output:但是,这是我想要的输出:
{'2'}
{'0'}
{'4', '5', '1', '8', '7', '6', '3', '0', '2', '9'}
How can I get the desired output?如何获得所需的输出?
I think this is what you want:我认为这就是你想要的:
seven_segment = {'0': {'a', 'c', 'd', 'e', 'b', 'f'},
'1': {'c', 'b'},
'2': {'a', 'd', 'e', 'b', 'g'},
'3': {'a', 'c', 'd', 'b', 'g'},
'4': {'g', 'c', 'f', 'b'},
'5': {'a', 'c', 'd', 'g', 'f'},
'6': {'a', 'c', 'd', 'e', 'g', 'f'},
'7': {'a', 'c', 'b'},
'8': {'a', 'c', 'd', 'e', 'b', 'g', 'f'},
'9': {'a', 'c', 'd', 'b', 'g', 'f'}}
def guess_damaged(display, state, damaged):
return {
key
for key, value in display.items()
if set(state) == (value - set(damaged))
}
print(guess_damaged(seven_segment, 'adeg', 'bf'))
print(guess_damaged(seven_segment, 'abed', 'cf'))
print(guess_damaged(seven_segment, '', 'abcdefg'))
output:输出:
{'2'}
{'0'}
{'7', '1', '5', '0', '9', '4', '2', '6', '3', '8'}
set
is very powerful built-in class. set
是非常强大的内置类。 reference page about set
关于set
参考页面
You can perform with set
:您可以使用set
执行:
|
)联合( |
)&
)相交( &
)-
)差异( -
)^
)对称差( ^
)<=
, <
, >
, >=
)子集关系( <=
, <
, >
, >=
)==
, !=
)相等( ==
, !=
)在排序时,seven_segment 字典中没有等于 'adeg' 或 'abed' 或 '' 的值,因此带有 "if (templist == sorted_state):" 的行永远不会为真
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