显示单选按钮选择php？

Question

My code works fine after the form fill out all values are print accept my gender value.

Here in the code below is an example imagine firstName,lastName.... the $row[dob] value prints out successfully.

But the option for the gender is not printing is there some array function i need to use for this to have the option selected bu the user print back on the screen when only display the details of the user (similar to a sticky form)?

    <li><label for='dateOfBirth'>DOB:</label>
    <input type='date' name='dateOfBirth' value = $row[dob] min='1900-01-01' max= '2015-01-01'/></li>

    <li>
        <input type='radio' name='gender' value=$row[gender]'>
        <label for='male'>Male</label><br>
        <input type='radio' name='gender' value='female'>
        <label for='female'>Female</label><br>
    </li>

Answer 1

you need to use the checked attribute

if the value that comes from $row['gender'] is male check the male radio otherwise check the female

like this

<li>
     <input type='radio' name='gender' <?= $row[gender] == 'male'? 'checked':'' ?> value='male'>
     <label for='male'>Male</label><br>
     <input type='radio' name='gender' <?= $row[gender] == 'female'? 'checked':'' ?> value='female'>
     <label for='female'>Female</label><br>
</li>

Answer 2

You shouldn't set the value of the radio inputs, instead determine if the value is checked.

Example:

<li>
    <input type='radio' name='gender' value='male' <?= $row['gender'] === 'male' ? 'checked' : null ?>>
    <label for='male'>Male</label><br>
    <input type='radio' name='gender' value='female' <?= $row['gender'] === 'female' ? 'checked' : null ?>>
    <label for='female'>Female</label><br>
</li>

NOTE: Your condition <?= $row['gender'] === 'female' ? 'checked' : null ?> <?= $row['gender'] === 'female' ? 'checked' : null ?> may vary depending on how you template your HTML.

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