删除python中数字列表中的重复数字

Question

I have seen some similar questions but not exactly what im asking, so: there cannot be a repeated digit in any of the other elements of the list, and if there's one repeated, only one must appear.

there's an input like: [12,22,12,2,34,25,9]

the output most be: [12,34,9] the 2, 22, 25,12 cannot be used because the first 12 have a 2 in it

I have made it to the point that i have [12,2,34,25,9] , but I'm not able to remove the repeated numbers. I have tried to separate each number to compare between each other, but i have not managed to do it.

Answer 1

Sets cannot have repeating entries so

l = [12,22,12,2,34,25,9]
l = list(set(l))

will produce the desired result.

EDIT:

def no_rep_digit(l):
    l_new = []
    digits = []
    for num in l:
        if not any([(digit in digits) for digit in str(num)]):
            l_new.append(num)
            digits.extend([digit for digit in str(num)])
        else:
            digits.extend([digit for digit in str(num)])
    return l_new

l = no_rep_digit(l)