如何打印匹配第一次出现的单词之间的所有行？

Question

input.txt

ABC
CDE
EFG
XYZ
ABC
PQR
EFG

From above file i want to print lines between 'ABC' and first occurrence of 'EFG'.

Expected output :

ABC
CDE
EFG
ABC
PQR
EFG 

How can i print lines from one word to first occurrence of second word?

Answer 1

EDIT: In case you want to print all occurrences of lines coming between ABC to DEF and leave others then try following.

awk '/ABC/{found=1} found;/EFG/{found=""}' Input_file

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Could you please try following.

awk '/ABC/{flag=1} flag && !count;/EFG/{count++}' Input_file

Answer 2

$ awk '/ABC/,/EFG/' file

Output:

ABC
CDE
EFG
ABC
PQR
EFG

Answer 3

This might work for you (GNU sed):

sed -n '/ABC/{:a;N;/EFG/!ba;p}' file

Turn off implicit printing by using the -n option.

Gather up lines between ABC and EFG and then print them. Repeat.

If you want to only print between the first occurrence of ABC to EFG , use:

sed -n '/ABC/{:a;N;/EFG/!ba;p;q}' file

To print the second through fourth occurrences, use:

sed -En '/ABC/{:a;N;/EFG/!ba;x;s/^/x/;/^x{2,4}$/{x;p;x};x;}' file