在bash中使用读取命令运行功能

Question

I need small help with shell function. I created small function with read command inside, I need to call this function and the return value to outside variable

Check()
{
echo "type something : "
read anyword
echo $anyword
}


out=`Check`
echo $out

the problem is that echo line is not presenting anything until i press enter. I want that this function will act like python.

Thanks,

Answer 1

The problem is the backticks. If you CTRL+C before the prompt ends, and try to echo $out , you notice that your prompt is saved into the $out variable. Move the prompt outside the function call. Maybe this will help:

Check()
{
    read anyword
    echo $anyword
}

echo "type something : "
out=`Check`
echo $out

If you're using bash specifically, consider read -p also.

Alternatively, if you want to keep the prompt inside the function:

Check()
{
    echo "Type something: " >&2
    read anyword
    echo $anyword
}

That way, it will write to stderr instead of stdout, so it won't get eaten up.