vim 搜索并替换为算术（C 指针）

Question

I want to search and replace a pointer

char* test

however, when I type

:%s/char* test/something/g

I get

E486: Pattern not found: char* test

I assume this is due to vim trying to use regex in search.

How can i tackle this issue? Is it possible to replace such text?

Answer 1

You need to escape star symbol. This should work:

:%s/char\* test/something/g

Answer 2

%s/char[[:blank:]]*[*][[:blank:]]*test/something/g

[[:blank:]]*[*][[:blank:]]* : To just replace "one" * occuring between any number of spaces or tabs. [1]

[1] What's the difference between [:space:] and [:blank:]?

Answer 3

如果您想完全禁用正则表达式，我找到了另一个解决方案

:%sno/char* test/something