如何将结构数组元素作为参数传递给函数？

Question

#include<stdio.h>
struct Ques
{
  int a;
}Q[5];
void sort(int a[])
{
 printf("any sort technique...");
}
void main() 
{
 sort(Q.a);
}

So this is the sample code. I Want to access the whole struct element as array.

Answer 1

You want this:

#include<stdio.h>

struct Ques
{
  int a;
} Q[5];

void sort(struct Ques array[], int size)
{
   printf("any sort technique...");

   // just some demo
   for (int i = 0; i < size; i++)
     printf("array[%d].a = %d\n", i, array[i].a);
}

int main() 
{
 // put some data into Q
 sort(Q, 5);
}

sort needs two parameters:

• the pointer to the array to sort
• the size of the array (unless you only ever want to sort array of some fixed size