如何查询 Express.js 中的特定内容？

Question

I have had the other issue resolved with the Leaderboard API not refreshing properly. I now have another issue with express Querying where I am trying to search a specific Discord ID. Using quick.db for my database and reusing part of the express.js code below that works on my other project to search for Different Ban Evidences by ID.

https://website.com/api/levelstats?id=DISCORDID

When I put the Discord ID into the above URL. It should parse the URL and output the following result in an Object:

app.get("/api/levelstats",  async function(request, response) {
  response.setHeader('Content-Type', 'application/json');
  if (!request.query.id) return response.send('null');
  let data;
  if (request.query.id !== 'all') data = await db.fetch('60Levelings', {
    target: request.query.id
  });
  else data = await db.fetch('60Levelings');
  if (!request.query.id !== 'all' && data) data.code = qs.parse(data.code).raw;
   response.send(JSON.stringify(data));
})

I've tried a different method which is params but to no success. I would appreciate any help, thanks.

Answer 1

You can try this :

app.get("/api/levelstats",  async function(request, response) {
  response.setHeader('Content-Type', 'application/json');
  if (!request.query.id) return response.send('null');
  let data;
  // change !== to != , maybe you can compare value only and ignore type data
  if (request.query.id != 'all') {
    // if request.query.id is not all, change type data request.query.id from string to int
    data = await db.fetch('60Levelings', {
      target: parseInt(request.query.id)
    });
    data.code = qs.parse(data.code).raw;
    response.send(JSON.stringify(data));
  }
  else {
    data = await db.fetch('60Levelings');
  }