如何获取字典中某个键的某个值？

Question

G={(-1, 1): [(0, 1)],
 (0, 0): [(1, 0), (0, 1)],
 (0, 1): [(1, 1), (0, 2), (-1, 1), (0, 0)],
 (0, 2): [(0, 1)],
 (1, 0): [(2, 0), (1, 1), (0, 0)],
 (1, 1): [(0, 1), (1, 0)],
 (2, 0): [(1, 0)]}

I have this dictionary in python and i want to go through each value of a certain key. For example i have the key: (0,0) I want to print each value seperately like this:

Output:

value 0 : (1,0)
value 1 : (0,1)

and I have this code

key=(0,0)
for v in range (len(G[key])):
    print ("value ", v, ":", G[(0,0)].get(v))

G[(0,0)].get(v) is wrong and i get a message:

AttributeError: 'list' object has no attribute 'get'

Do you know what should i use instead?

Answer 1

enumerate will get you the index and value:

key=(0,0)
for idx,v in enumerate(G[key]):
    print ("value ", idx, ":", v)

Answer 2

you can use print build-in function with param sep='\\n' :

print(*G[(0,0)], sep='\n')

output:

(1, 0)
(0, 1)

or you can use:

print(*['value %s : %s' % t for t in enumerate(G[(0,0)])], sep='\n')

output:

value 0 : (1, 0)
value 1 : (0, 1)