取 CSV 的第一行并将其转换为新列中的默认值

Question

I have a fussy file export that basically creates a CSV with an odd format like:

filename, date
header1, header2, header3, header4
value1, value2, value3, value4
value5, value6, value7, value8

I'm trying to take that 'date' field from the first row and create a 5th column with that value as the default value.

I then want to delete that first row entirely. Deleting the row isn't the issue, I just can't think of a way of selecting that date value and turning it into a new column.

Answer 1

You'll use the csv library to read like so:

import csv

with open('path_to_file_', 'r') as fh:
    reader = csv.reader(fh)

    # first get the date
    first_line = next(reader)
    date = first_line[1]

    # read the rest and add the date to every line
    lines = [l.append(date) for l in list(reader)]