[英]skos broader and narrow inverse not working
I have setup GraphDB SE trial version and trying out inference functionality with OWL2-RL ruleset.我已经设置了 GraphDB SE 试用版并尝试使用 OWL2-RL 规则集进行推理功能。 I have built a simple SKOS knowledge with a single broader relationship.我已经建立了一个简单的 SKOS 知识和一个更广泛的关系。 Some how, when I try to query for narrower relationship am not getting any results.某种方式,当我尝试查询更窄的关系时没有得到任何结果。 Am I going wrong in the usage ?我在使用上会出错吗?
Insertion:插入:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
PREFIX owl: <http://www.w3.org/2002/07/owl#>
INSERT DATA {
ex:mammals rdf:type skos:Concept;
skos:prefLabel "mammals"@en;
ex:animals rdf:type skos:Concept;
skos:prefLabel "animals"@en;
skos:broader ex:mammals .
}
Query:询问:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
PREFIX skos: <http://www.w3.org/2004/02/skos/core#>
select * where {
?s skos:narrower ?o .
}
In the query result I don't see any response.在查询结果中,我没有看到任何响应。 Shouldn't it return below result - ex:mammals skos:narrower ex:animals它不应该返回以下结果吗 - ex:mammals skos:narrower ex:animals
I just came across this question and the OP is correct: Although the official SKOS reference explicitly states that skos:broader
and skos:narrower
are inverse, the actual RDF implementation does not include this statement.我刚刚遇到了这个问题,并且 OP 是正确的:虽然官方 SKOS 参考明确指出skos:broader
和skos:narrower
是相反的,但实际的 RDF 实现不包括这个语句。 However, properties skos:broaderTransitive
and skos:narrowerTransitive
are declared as inverse.但是,属性skos:broaderTransitive
和skos:narrowerTransitive
被声明为逆属性。
And, although not relevant to the original question, the implementation does not state properties skos:topConceptOf
and skos:hasTopConcept
as inverse either.而且,虽然与原始问题无关,但实现也没有将属性skos:topConceptOf
和skos:hasTopConcept
为相反的。
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