如何在python中制作一个二维元组数组？

Question

I want to make a 2D array of 2-tuples of fixed dimension (say 10x10).我想制作一个固定维度（比如 10x10）的 2 元组的二维数组。

eg例如

[[(1,2), (1,2), (1,2)],
 [(1,2), (1,2), (1,2)],
 [(1,2), (1,2), (1,2)]]

There are also two ways that I'd like to generate this array:我还想通过两种方式生成此数组：

An array like the example above where every element is the same tuple一个像上面例子一样的数组，其中每个元素都是同一个元组
An array which I populate iteratively with specific tuples (possibly starting with an empty array of fixed size and then using assignment)我用特定元组迭代填充的数组（可能从固定大小的空数组开始，然后使用赋值）

How would I go about doing this?我该怎么做呢？ For #1 I tried using numpy.tiles :对于#1，我尝试使用numpy.tiles ：

>>> np.tile(np.array([1,2]), (3, 3))
array([[1, 2, 1, 2, 1, 2],
       [1, 2, 1, 2, 1, 2],
       [1, 2, 1, 2, 1, 2]])

But I can't seem to copy it across columns, the columns are just concatenated.但我似乎无法跨列复制它，这些列只是连接在一起。

ie instead of:即而不是：

[[[1,2], [1,2], [1,2]],
 [[1,2], [1,2], [1,2]],
 [[1,2], [1,2], [1,2]]]

Answer 1

you can use numpy.full :你可以使用numpy.full ：

numpy.full((3, 3, 2), (1, 2))

output:输出：

array([[[1, 2],
        [1, 2],
        [1, 2]],

       [[1, 2],
        [1, 2],
        [1, 2]],

       [[1, 2],
        [1, 2],
        [1, 2]]])

Answer 2

for <1> you can generate like this对于 <1> 你可以这样生成

[[(1,2)] * 3]*3
# get [[(1, 2), (1, 2), (1, 2)], [(1, 2), (1, 2), (1, 2)], [(1, 2), (1, 2), (1, 2)]]

Answer 3

numpy.zeros((3,3,2))

我想会起作用（但它不是它的列表的元组......）