当使用 eval() 从 php 脚本调用脚本以及从 bash 脚本调用相同的函数时，python 如何使用路径？

Question

I have an executable python script which archives data from mysql server using the pymysql library. The script works well from the command line.

I call this script from a php script using escapeshellcmd function and I've gotten it to work.

I also have created a bash script that I intend to use from crontab to archive the information as well. I can make this script work as well, by making changes outlined below.

Somehow I have gotten into python versions and path problems.

if I include

#!/home/tim/anaconda3/bin/python

as the first line of the python script it works when called by the php script (using www-data as the user, I believe). It doesn't work from the bash script or the command line, giving the following error:

  File "./signal_archive.py", line 22, in <module>
    import pymysql
ModuleNotFoundError: No module named 'pymysql'

However, if the first line of the python script is as follows:

#!/usr/bin/python3

the script works from the bash script and the command line but not from the php script. It gives the following error:

  File "/home/tim/python/commodities_related/signal_archive.py", line 23, in <module>
    import pandas as pd
ModuleNotFoundError: No module named 'pandas'

Both packages are installed on my system. Thinking pointing the script to the path would help, I added the following to the python script but no luck so far.

sys.path.append('/usr/lib/python3/dist-packages:')
sys.path.append('/usr/local/lib/python3.5/dist-packages:')

There is obviously something I'm missing; I think it is that php script is called by www-user and I don't know the default path. The bash file is called by my user with the path specified in the .bashrc file. However, I may need to point the apache or php (www-user) to use a specific installation of python.

EDIT- To be more clear, a php script (phpfile1.php) calls the python script. When I call phpfile1.php from another php script (phpfile2.php) running on apache2 I everything works using the

#!/home/tim/anaconda3/bin/python

When I call the same file (phpfile1.php) from a different php script (phpfile3.php) from a bash script it fails. Additionally, if I run the file in place using the following

./signal_archive.py

I get the error but if I run it using the following command it works:

python signal_archive.py

Any ideas if this is right or how to do it? Thanks.

Answer 1

I fixed this in 2 steps:

It turns out that I needed to add the path to anaconda3 to my .bash_profile file.

export PATH="/home/tim/anaconda3/bin:$PATH"

When anaconda3 is installed it modifies the .bashrc file with the previous code snippet. However .bash_profile made the difference in this case.

I also modified the top of the python file to use the anaconda path for execution, as well as add the path for the specific python packages.

#!/home/tim/anaconda3/bin/python
import sys
sys.path.insert(1, '/usr/local/lib/python3.5/dist-packages')