[英]How to easily implement conditional count in groupby using Java Stream
I have the following data(A class structure):我有以下数据(一个类结构):
[
{
"name": "a",
"enable": true
},
{
"name": "a",
"enable": false
},
{
"name": "b",
"enable": false
},
{
"name": "b",
"enable": false
},
{
"name": "c",
"enable": false
}
]
How can I replace the complex code below with a simple steam:如何用简单的蒸汽替换下面的复杂代码:
List<A> list = xxxxx;
Map<String, Integer> aCountMap = new HashMap<>();
list.forEach(item -> {
Integer count = aCountMap.get(item.getName());
if (Objects.isNull(count)) {
aCountMap.put(item.getName(), 0);
}
if (item.isEnable()) {
aCountMap.put(item.getName(), ++count);
}
});
The correct result is as follows:正确结果如下:
{"a":1}
{"b":0}
{"c":0}
You might simply be counting the objects filtered by a condition:您可能只是在计算按条件过滤的对象:
Map<String, Long> aCountMap = list.stream()
.filter(A::isEnable)
.collect(Collectors.groupingBy(A::getName, Collectors.counting()));
But since you are looking for the 0
count as well, Collectors.filtering
with Java-9+ provides you the implementation such as :但是由于您也在寻找0
计数,Java-9+ 的Collectors.filtering
为您提供了如下实现:
Map<String, Long> aCountMap = List.of().stream()
.collect(Collectors.groupingBy(A::getName,
Collectors.filtering(A::isEnable,
Collectors.counting())));
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