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在 C++ 中的行上压缩的稀疏矩阵

[英]Sparse matrix compressed on rows in C++

I have to implement the CSR matrix data structure in C++ using 3 dynamic arrays (indexing starts at 0) and I've got stuck.我必须使用 3 个动态数组(索引从 0 开始)在 C++ 中实现 CSR 矩阵数据结构,但我被卡住了。 So I have to implement 2 functions:所以我必须实现2个功能:

1) modify(int i, int j, TElem e) - modifies the value of (i,j) to e or adds if (if it does not exist) or deletes it if e is null. 1) modify(int i, int j, TElem e) - 将 (i,j) 的值修改为 e 或添加 if(如果不存在)或在 e 为空时删除它。

2) element(int i, int j) const - returns the value found on (i,j) 2) element(int i, int j) const - 返回在 (i,j) 上找到的值

I wanted to test my code in the next way:我想以下一种方式测试我的代码:

Matrix m(4,4);矩阵 m(4,4); m.print(); m.print(); It will print:它会打印:

Lines: 0 0 0 0 0行:0 0 0 0 0

Columns:列:

Values:价值观:

(And this is fine) (这很好)

Now if I want to modify: m.modify(1,1,5);现在如果我想修改: m.modify(1,1,5); //The element (1,1) will be set to 5 //元素(1,1)将被设置为5

The output of m.print(); m.print() 的输出; will be:将会:

Lines: 0 1 1 1 1行数:0 1 1 1 1

Columns: 1列:1

Values: 5 (which again is fine)值:5(这也很好)

And now if I want to print m.element(1, 1) it will return 0 and m.element(0, 1) will return 5.现在如果我想打印 m.element(1, 1) 它将返回 0 而 m.element(0, 1) 将返回 5。

This is my implementation of element(int i, int j) :这是我对 element(int i, int j) 的实现:

    int currCol;
    for (int pos = this->lines[i]; pos < this->lines[i+1]; pos++) {
        currCol = this->columns[pos];
        if (currCol == j)
            return this->values[pos];
        else if (currCol > j)
            break;
    }
    return NULL_TELEM;

The constructor looks like this:构造函数如下所示:

Matrix::Matrix(int nrLines, int nrCols) {
    if (nrLines <= 0 || nrCols <= 0)
        throw exception();
    this->nr_lines = nrLines;
    this->nr_columns = nrCols;
    this->values = new TElem[100];
    this->values_capacity = 1;
    this->values_size = 0; 
    this->lines = new int[nrLines + 1];
    this->columns = new TElem[100];
    this->columns_capacity = 1;
    this->columns_size = 0; 
    for (int i = 0; i <= nrLines; i++)
        this->lines[i] = NULL_TELEM;
}

This is the "modify" method:这是“修改”方法:

TElem Matrix::modify(int i, int j, TElem e) {
    if (i < 0 || j < 0 || i >= this->nr_lines || j >= nr_columns)
        throw exception();
    int pos = this->lines[i];
    int currCol = 0;
    for (; pos < this->lines[i + 1]; i++) {
        currCol = this->columns[pos];
        if (currCol >= j)
            break;
    }
    if (currCol != j) {
        if (!(e == 0)) 
            add(pos, i, j, e);
    }
    else if (e == 0)
        remove(pos, i);
    else
        this->values[pos] = e;
    return NULL_TELEM;
}

And this is the inserting method:这是插入方法:

void Matrix::add(int index, int line, int column, TElem value)
{
    this->columns_size++;
    this->values_size++;
    for (int i = this->columns_size; i >= index + 1; i--) {
        this->columns[i] = this->columns[i - 1];
        this->values[i] = this->values[i - 1];
    }
    this->columns[index] = column;
    this->values[index] = value;
    for (int i = line; i <= this->nr_lines; i++) //changed to i = line + 1;
        this->lines[i]++;
}

Can somebody help me, please?有人可以帮我吗? I can't figure out why this happens and I really need to finish this implementation these days.我不知道为什么会发生这种情况,这些天我真的需要完成这个实现。

It just can't pass the next test.它只是无法通过下一个测试。 And if I want to print the elements i have (4,0)=0 (4,1)=0 ... (4,8)=0 and (4,9)=3.如果我想打印元素,我有 (4,0)=0 (4,1)=0 ... (4,8)=0 和 (4,9)=3。 Now this looks pretty weird why it happens.现在这看起来很奇怪为什么会发生。

void testModify() {
    cout << "Test modify" << endl;
    Matrix m(10, 10);
    for (int j = 0; j < m.nrColumns(); j++)
        m.modify(4, j, 3);
    for (int i = 0; i < m.nrLines(); i++)
        for (int j = 0; j < m.nrColumns(); j++)
            if (i == 4)
                assert(m.element(i, j) == 3);
                //cout << i << " " << j << ":" << m.element(i, j)<<'\n';
            else
                assert(m.element(i, j) == NULL_TELEM);
}

When you call modify(1, 1, 5) with an empty matrix (all zeros), that results in a call to add(0, 1, 1, 5) .当您使用空矩阵(全为零)调用modify(1, 1, 5)时,会导致调用add(0, 1, 1, 5) That increments columns_size and values_size (both to 1 ), the for loop body will not execute, you update columns[0] to 1 and values[0] to 5 , then increment all the lines values starting at element lines[1] , setting them all to 1 ( lines[0] will still be 0 ).这会增加columns_sizevalues_size (都为1 ),for 循环体将不会执行,您将columns[0]更新为1并将values[0]5 ,然后从元素lines[1]开始增加所有lines值,设置它们全部为 1( lines[0]仍将是0 )。 But lines[1] should indicate the element we just added, so it should be 0 , since the value is found using columns[0] .但是lines[1]应该表示我们刚刚添加的元素,所以它应该是0 ,因为该值是使用columns[0]

The for loop at the end of add should start at element line + 1 . add末尾的 for 循环应该从元素line + 1

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