避免命名函数调用的 Webpack 配置

Question

I want to trade disk space for no named function calling in webpack so that I can do language analysis easier.

However webpack' ing the following modules,

• index.js import foo.js; foo() import foo.js; foo()
  • foo.js import bar.js; console.log(bar()) console.log(bar()) console.log(bar()) import bar.js; console.log(bar()) console.log(bar()) console.log(bar())
    • bar.js return "THIS IS BAR!"

Results in:

function bar() { return "THIS IS BAR!"; }
function foo() {
  console.log(bar());
  console.log(bar());
  console.log(bar());
}
foo();

And I want,

function foo() {
  console.log((() => { return "THIS IS BAR!" })());
  console.log((() => { return "THIS IS BAR!" })());
  console.log((() => { return "THIS IS BAR!" })());
}
foo();

Even while this will increase the space of the bundle. Because I want to avoid function calling.

How can I do this?

So far I have tried with several { optimization: { ... } } rules but none of them leads to the desired result.

Answer 1

Did you try with the mode production. With current setting. I can see desire output.

// foo.js

import bar from './bar'
export default function print() {
    console.log(bar())
    console.log(bar())
    console.log(bar())
}

// bar.js

export default function bar() {
    return "THIS IS TEST"
}

// webpack.config.js

const path = require('path');

module.exports = {
    mode: "production",
  entry: './src/foo.js',
  output: {
    path: path.resolve(__dirname, 'dist'),
    filename: 'foo.bundle.js'
  }
};

// Version

"webpack": "^4.42.0", "webpack-cli": "^3.3.11"

// Output

([function(e,t,n){"use strict";function r(){console.log("THIS IS TEST"),console.log("THIS IS TEST"),console.log("THIS IS TEST")}n.r(t),n.d(t,"default",(function(){return r}))}]);