正则表达式“以 a 开头并以 b 结尾的 a 和 b 数量相等的字符串”。
[英]Regex for "strings of equal number of a's and b's that beginns with an a and ending with b."r
问题描述
I am trying to find regex for "strings of equal number of a's and b's that beginns with an a and ending with b."
我正在尝试为“以 a 开头并以 b 结尾的相同数量的 a 和 b 的字符串”找到正则表达式。
Here is what i've done : https://regex101.com/r/6sEGqm/1/这是我所做的： https : //regex101.com/r/6sEGqm/1/
1 个解决方案
解决方案1
0 2020-03-24 04:36:59
如果你不需要像abbaab这样的abbaab那么你去：
/^(?:ab)+?$/
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.
相关问题
正则表达式，用于仅包含集合为{a，b}的b的奇数簇的字符串 - Regex for strings that contain only odd clusters of b's with set {a,b}
正则表达式：为r：a。？b。？c创建例外 - regex: creating an exception for r:a.?b.?c
查找包含偶数个a和偶数个b的所有a和b字符串的正则表达式？ - Regular expression to find all strings of a's and b's that contain an even number of a's and an even number of b's?
正则表达式没有连续2个a和b - Regex with no 2 consecutive a's and b's
用于在单词A和单词B. findstr，Regex或替代项之间查找文本字符串的脚本 - Script to find text strings between word A and word B. findstr, Regex, or alternatives
包含a和偶数b的字符串的正则表达式 - Regular expression for strings that cointains a and an even number of b's
在perl中编写一个正则表达式，用于a的序列，后跟相等数量的b - to write a regular expression in perl for sequence of a's followed by an equal number of b's
带有偶数个 b 后跟字母 c 后跟奇数个 a 的字符串的正则表达式 - Regular Expression for Strings with even number of b's followed by the letter c followed by an odd number of a's
R：在正则表达式中使用 \\b 和 \\B - R: using \\b and \\B in regex
s | \\ bd \\ b || 正则表达式无法正常工作 - s|\b-d\b|| regex not working as expected
相关标签